The equation of motion of a simple harmonic oscillator is given by x(t) = 0.4 cos (nt/2 + π/4). At what time will the oscillator pass by the equilibrium positio
Physique/Chimie
shazaaa
Question
The equation of motion of a simple harmonic oscillator is given by x(t) = 0.4 cos
(nt/2 + π/4). At what time will the oscillator pass by the equilibrium position, x = 0,
for the first time?
(nt/2 + π/4). At what time will the oscillator pass by the equilibrium position, x = 0,
for the first time?